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7v^2-34v-44=4
We move all terms to the left:
7v^2-34v-44-(4)=0
We add all the numbers together, and all the variables
7v^2-34v-48=0
a = 7; b = -34; c = -48;
Δ = b2-4ac
Δ = -342-4·7·(-48)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-50}{2*7}=\frac{-16}{14} =-1+1/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+50}{2*7}=\frac{84}{14} =6 $
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